Integrand size = 20, antiderivative size = 159 \[ \int \frac {x^{5/2} (A+B x)}{\sqrt {a+b x}} \, dx=\frac {5 a^2 (8 A b-7 a B) \sqrt {x} \sqrt {a+b x}}{64 b^4}-\frac {5 a (8 A b-7 a B) x^{3/2} \sqrt {a+b x}}{96 b^3}+\frac {(8 A b-7 a B) x^{5/2} \sqrt {a+b x}}{24 b^2}+\frac {B x^{7/2} \sqrt {a+b x}}{4 b}-\frac {5 a^3 (8 A b-7 a B) \text {arctanh}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a+b x}}\right )}{64 b^{9/2}} \]
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Time = 0.05 (sec) , antiderivative size = 159, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {81, 52, 65, 223, 212} \[ \int \frac {x^{5/2} (A+B x)}{\sqrt {a+b x}} \, dx=-\frac {5 a^3 (8 A b-7 a B) \text {arctanh}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a+b x}}\right )}{64 b^{9/2}}+\frac {5 a^2 \sqrt {x} \sqrt {a+b x} (8 A b-7 a B)}{64 b^4}-\frac {5 a x^{3/2} \sqrt {a+b x} (8 A b-7 a B)}{96 b^3}+\frac {x^{5/2} \sqrt {a+b x} (8 A b-7 a B)}{24 b^2}+\frac {B x^{7/2} \sqrt {a+b x}}{4 b} \]
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Rule 52
Rule 65
Rule 81
Rule 212
Rule 223
Rubi steps \begin{align*} \text {integral}& = \frac {B x^{7/2} \sqrt {a+b x}}{4 b}+\frac {\left (4 A b-\frac {7 a B}{2}\right ) \int \frac {x^{5/2}}{\sqrt {a+b x}} \, dx}{4 b} \\ & = \frac {(8 A b-7 a B) x^{5/2} \sqrt {a+b x}}{24 b^2}+\frac {B x^{7/2} \sqrt {a+b x}}{4 b}-\frac {(5 a (8 A b-7 a B)) \int \frac {x^{3/2}}{\sqrt {a+b x}} \, dx}{48 b^2} \\ & = -\frac {5 a (8 A b-7 a B) x^{3/2} \sqrt {a+b x}}{96 b^3}+\frac {(8 A b-7 a B) x^{5/2} \sqrt {a+b x}}{24 b^2}+\frac {B x^{7/2} \sqrt {a+b x}}{4 b}+\frac {\left (5 a^2 (8 A b-7 a B)\right ) \int \frac {\sqrt {x}}{\sqrt {a+b x}} \, dx}{64 b^3} \\ & = \frac {5 a^2 (8 A b-7 a B) \sqrt {x} \sqrt {a+b x}}{64 b^4}-\frac {5 a (8 A b-7 a B) x^{3/2} \sqrt {a+b x}}{96 b^3}+\frac {(8 A b-7 a B) x^{5/2} \sqrt {a+b x}}{24 b^2}+\frac {B x^{7/2} \sqrt {a+b x}}{4 b}-\frac {\left (5 a^3 (8 A b-7 a B)\right ) \int \frac {1}{\sqrt {x} \sqrt {a+b x}} \, dx}{128 b^4} \\ & = \frac {5 a^2 (8 A b-7 a B) \sqrt {x} \sqrt {a+b x}}{64 b^4}-\frac {5 a (8 A b-7 a B) x^{3/2} \sqrt {a+b x}}{96 b^3}+\frac {(8 A b-7 a B) x^{5/2} \sqrt {a+b x}}{24 b^2}+\frac {B x^{7/2} \sqrt {a+b x}}{4 b}-\frac {\left (5 a^3 (8 A b-7 a B)\right ) \text {Subst}\left (\int \frac {1}{\sqrt {a+b x^2}} \, dx,x,\sqrt {x}\right )}{64 b^4} \\ & = \frac {5 a^2 (8 A b-7 a B) \sqrt {x} \sqrt {a+b x}}{64 b^4}-\frac {5 a (8 A b-7 a B) x^{3/2} \sqrt {a+b x}}{96 b^3}+\frac {(8 A b-7 a B) x^{5/2} \sqrt {a+b x}}{24 b^2}+\frac {B x^{7/2} \sqrt {a+b x}}{4 b}-\frac {\left (5 a^3 (8 A b-7 a B)\right ) \text {Subst}\left (\int \frac {1}{1-b x^2} \, dx,x,\frac {\sqrt {x}}{\sqrt {a+b x}}\right )}{64 b^4} \\ & = \frac {5 a^2 (8 A b-7 a B) \sqrt {x} \sqrt {a+b x}}{64 b^4}-\frac {5 a (8 A b-7 a B) x^{3/2} \sqrt {a+b x}}{96 b^3}+\frac {(8 A b-7 a B) x^{5/2} \sqrt {a+b x}}{24 b^2}+\frac {B x^{7/2} \sqrt {a+b x}}{4 b}-\frac {5 a^3 (8 A b-7 a B) \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a+b x}}\right )}{64 b^{9/2}} \\ \end{align*}
Time = 0.47 (sec) , antiderivative size = 126, normalized size of antiderivative = 0.79 \[ \int \frac {x^{5/2} (A+B x)}{\sqrt {a+b x}} \, dx=\frac {\sqrt {x} \sqrt {a+b x} \left (-105 a^3 B+16 b^3 x^2 (4 A+3 B x)-8 a b^2 x (10 A+7 B x)+10 a^2 b (12 A+7 B x)\right )}{192 b^4}+\frac {5 a^3 (-8 A b+7 a B) \text {arctanh}\left (\frac {\sqrt {b} \sqrt {x}}{-\sqrt {a}+\sqrt {a+b x}}\right )}{32 b^{9/2}} \]
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Time = 0.51 (sec) , antiderivative size = 135, normalized size of antiderivative = 0.85
method | result | size |
risch | \(\frac {\left (48 b^{3} B \,x^{3}+64 A \,b^{3} x^{2}-56 B a \,b^{2} x^{2}-80 a \,b^{2} A x +70 a^{2} b B x +120 a^{2} b A -105 a^{3} B \right ) \sqrt {x}\, \sqrt {b x +a}}{192 b^{4}}-\frac {5 a^{3} \left (8 A b -7 B a \right ) \ln \left (\frac {\frac {a}{2}+b x}{\sqrt {b}}+\sqrt {b \,x^{2}+a x}\right ) \sqrt {x \left (b x +a \right )}}{128 b^{\frac {9}{2}} \sqrt {x}\, \sqrt {b x +a}}\) | \(135\) |
default | \(-\frac {\sqrt {x}\, \sqrt {b x +a}\, \left (-96 B \,b^{\frac {7}{2}} x^{3} \sqrt {x \left (b x +a \right )}-128 A \,b^{\frac {7}{2}} x^{2} \sqrt {x \left (b x +a \right )}+112 B a \,b^{\frac {5}{2}} x^{2} \sqrt {x \left (b x +a \right )}+160 A \sqrt {x \left (b x +a \right )}\, b^{\frac {5}{2}} a x -140 B \sqrt {x \left (b x +a \right )}\, b^{\frac {3}{2}} a^{2} x +120 A \ln \left (\frac {2 \sqrt {x \left (b x +a \right )}\, \sqrt {b}+2 b x +a}{2 \sqrt {b}}\right ) a^{3} b -240 A \sqrt {x \left (b x +a \right )}\, b^{\frac {3}{2}} a^{2}-105 B \ln \left (\frac {2 \sqrt {x \left (b x +a \right )}\, \sqrt {b}+2 b x +a}{2 \sqrt {b}}\right ) a^{4}+210 B \sqrt {x \left (b x +a \right )}\, \sqrt {b}\, a^{3}\right )}{384 b^{\frac {9}{2}} \sqrt {x \left (b x +a \right )}}\) | \(218\) |
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Time = 0.24 (sec) , antiderivative size = 249, normalized size of antiderivative = 1.57 \[ \int \frac {x^{5/2} (A+B x)}{\sqrt {a+b x}} \, dx=\left [-\frac {15 \, {\left (7 \, B a^{4} - 8 \, A a^{3} b\right )} \sqrt {b} \log \left (2 \, b x - 2 \, \sqrt {b x + a} \sqrt {b} \sqrt {x} + a\right ) - 2 \, {\left (48 \, B b^{4} x^{3} - 105 \, B a^{3} b + 120 \, A a^{2} b^{2} - 8 \, {\left (7 \, B a b^{3} - 8 \, A b^{4}\right )} x^{2} + 10 \, {\left (7 \, B a^{2} b^{2} - 8 \, A a b^{3}\right )} x\right )} \sqrt {b x + a} \sqrt {x}}{384 \, b^{5}}, -\frac {15 \, {\left (7 \, B a^{4} - 8 \, A a^{3} b\right )} \sqrt {-b} \arctan \left (\frac {\sqrt {b x + a} \sqrt {-b}}{b \sqrt {x}}\right ) - {\left (48 \, B b^{4} x^{3} - 105 \, B a^{3} b + 120 \, A a^{2} b^{2} - 8 \, {\left (7 \, B a b^{3} - 8 \, A b^{4}\right )} x^{2} + 10 \, {\left (7 \, B a^{2} b^{2} - 8 \, A a b^{3}\right )} x\right )} \sqrt {b x + a} \sqrt {x}}{192 \, b^{5}}\right ] \]
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Time = 47.22 (sec) , antiderivative size = 303, normalized size of antiderivative = 1.91 \[ \int \frac {x^{5/2} (A+B x)}{\sqrt {a+b x}} \, dx=\frac {5 A a^{\frac {5}{2}} \sqrt {x}}{8 b^{3} \sqrt {1 + \frac {b x}{a}}} + \frac {5 A a^{\frac {3}{2}} x^{\frac {3}{2}}}{24 b^{2} \sqrt {1 + \frac {b x}{a}}} - \frac {A \sqrt {a} x^{\frac {5}{2}}}{12 b \sqrt {1 + \frac {b x}{a}}} - \frac {5 A a^{3} \operatorname {asinh}{\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}} \right )}}{8 b^{\frac {7}{2}}} + \frac {A x^{\frac {7}{2}}}{3 \sqrt {a} \sqrt {1 + \frac {b x}{a}}} - \frac {35 B a^{\frac {7}{2}} \sqrt {x}}{64 b^{4} \sqrt {1 + \frac {b x}{a}}} - \frac {35 B a^{\frac {5}{2}} x^{\frac {3}{2}}}{192 b^{3} \sqrt {1 + \frac {b x}{a}}} + \frac {7 B a^{\frac {3}{2}} x^{\frac {5}{2}}}{96 b^{2} \sqrt {1 + \frac {b x}{a}}} - \frac {B \sqrt {a} x^{\frac {7}{2}}}{24 b \sqrt {1 + \frac {b x}{a}}} + \frac {35 B a^{4} \operatorname {asinh}{\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}} \right )}}{64 b^{\frac {9}{2}}} + \frac {B x^{\frac {9}{2}}}{4 \sqrt {a} \sqrt {1 + \frac {b x}{a}}} \]
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Time = 0.20 (sec) , antiderivative size = 206, normalized size of antiderivative = 1.30 \[ \int \frac {x^{5/2} (A+B x)}{\sqrt {a+b x}} \, dx=\frac {\sqrt {b x^{2} + a x} B x^{3}}{4 \, b} - \frac {7 \, \sqrt {b x^{2} + a x} B a x^{2}}{24 \, b^{2}} + \frac {\sqrt {b x^{2} + a x} A x^{2}}{3 \, b} + \frac {35 \, \sqrt {b x^{2} + a x} B a^{2} x}{96 \, b^{3}} - \frac {5 \, \sqrt {b x^{2} + a x} A a x}{12 \, b^{2}} + \frac {35 \, B a^{4} \log \left (2 \, b x + a + 2 \, \sqrt {b x^{2} + a x} \sqrt {b}\right )}{128 \, b^{\frac {9}{2}}} - \frac {5 \, A a^{3} \log \left (2 \, b x + a + 2 \, \sqrt {b x^{2} + a x} \sqrt {b}\right )}{16 \, b^{\frac {7}{2}}} - \frac {35 \, \sqrt {b x^{2} + a x} B a^{3}}{64 \, b^{4}} + \frac {5 \, \sqrt {b x^{2} + a x} A a^{2}}{8 \, b^{3}} \]
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Time = 151.79 (sec) , antiderivative size = 225, normalized size of antiderivative = 1.42 \[ \int \frac {x^{5/2} (A+B x)}{\sqrt {a+b x}} \, dx=\frac {\frac {8 \, {\left (\frac {15 \, a^{3} \log \left ({\left | -\sqrt {b x + a} \sqrt {b} + \sqrt {{\left (b x + a\right )} b - a b} \right |}\right )}{b^{\frac {3}{2}}} + \sqrt {{\left (b x + a\right )} b - a b} \sqrt {b x + a} {\left (2 \, {\left (b x + a\right )} {\left (\frac {4 \, {\left (b x + a\right )}}{b^{2}} - \frac {13 \, a}{b^{2}}\right )} + \frac {33 \, a^{2}}{b^{2}}\right )}\right )} A {\left | b \right |}}{b^{2}} - \frac {{\left (\frac {105 \, a^{4} \log \left ({\left | -\sqrt {b x + a} \sqrt {b} + \sqrt {{\left (b x + a\right )} b - a b} \right |}\right )}{b^{\frac {5}{2}}} - {\left (2 \, {\left (b x + a\right )} {\left (4 \, {\left (b x + a\right )} {\left (\frac {6 \, {\left (b x + a\right )}}{b^{3}} - \frac {25 \, a}{b^{3}}\right )} + \frac {163 \, a^{2}}{b^{3}}\right )} - \frac {279 \, a^{3}}{b^{3}}\right )} \sqrt {{\left (b x + a\right )} b - a b} \sqrt {b x + a}\right )} B {\left | b \right |}}{b^{2}}}{192 \, b} \]
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Timed out. \[ \int \frac {x^{5/2} (A+B x)}{\sqrt {a+b x}} \, dx=\int \frac {x^{5/2}\,\left (A+B\,x\right )}{\sqrt {a+b\,x}} \,d x \]
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